Question

x÷y+y÷x =-1 then the value of x³-y³​

Answer 1

Answer: 0

Step-by-step explanation:

We know that,

x³-y³=(x-y)(x²+xy+y²)          ........................1

Given that,

x/y+y/x=-1

(x²+y²)/xy= -1

⇒x²+y²=-xy

⇒x²+y²+xy=0

⇒(x²+xy+y²)=0

Multiplying by (x-y) on both sides we get,

⇒ (x-y)(x²+xy+y²)=(x-y)×0

By eq1 we get,

x³-y³=0

Hence x³-y³=0.

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