Question

x/y+y/x=-1 when x not equal to 0 then the value (x^3 - y^3) =?​

Answer 1

Answer:

0

Step-by-step explanation:

x/y+y/x=-1

x2+y2=-xy------(1)

(x3-y3)=(x-y)(x2+y2+xy)-----------(2)

substitute 1 in 2

(x3-y3)=(x-y)(-xy+xy)=0

Answer 2

solution

$= > \frac{x}{y} + \frac{y}{x} = - 1 \\ = > \frac{x {}^{2} + y {}^{2} }{xy} = - 1 \\ = > x {}^{2} + y {}^{2} = - xy \\ = > x {}^{2} + y {}^{2} + xy = 0 \\ now...... \\ x {}^{3} - y {}^{3} = (x - y)(x {}^{2} + y {}^{2} + xy) \\ = > x {}^{3} - y {}^{3} = (x - y) \times 0 = 0$