Question

x^y+y^x=19,then find the value of x-y​

Answer 1

The values of X & Y are 3 & 2. I have randomly assumed value of X as 3 & Y as 2 but it can be X=2 or Y=3 the final answer will be remain the same.

3+2=5.................(as per question)

now it proves 3^2+2^3=17 i.e 9+8=17

On the other hand if we assumed the values of X&Y 1 &4 instead of 3 & 2 this will not prove the answer

Hence Answer is 2 & 3are the values