x^y=y^x then find (x/y)^x/y
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x^y=y^x
x = y^x/y.
Also, x^y/x = y.
Now,
(x/y)^x/y
=( x ^ x/y )/x
= x ^ x/y - 1
x = y^x/y.
Also, x^y/x = y.
Now,
(x/y)^x/y
=( x ^ x/y )/x
= x ^ x/y - 1
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