Math, asked by shawnk, 1 year ago

x^y.y^x=x^x find Dy/dx​

Answers

Answered by arham9dedhia
2

Answer :dy/dx=x^y*y^x=x^x

=yx^y-1*y^x=x*x^x-1

=yx^y-1*y^x=x^2(x-1)

=yx^y-1*y^x=x^2x-2

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