Math, asked by Javeriyashaikh5531, 8 months ago

(x-y)(y+x)+(y-z)(z+y)=xsq.-zsq.

Answers

Answered by pranalinalode4
0

HERE IS YOUR ANSWER

STEP BY STEP EXPLANATION:

=(X-Y)(X+Y)+(Y-Z)(Z+Y),

=X^2+Y^2-Y^2-Z^2,

=X^2-Z^2

HERE IS YOUR ANSWER

MARK BRAINLIEST, PLEASE!!

Answered by YashChamle
0

Answer:

Given equation :-

=> ( x + y)(x - y) + (y - z)(y + z)

we know that (a + b)(a - b) = a² - b²

=> (x + y)(x - y) = x² - y²

=> ( y + z)( y - z) = y² - z²

So, (x + y)(x - y) + ( y + z)(y - z) = x² - y² + y² - z²

So, the answer you'll get is x² - z²

plz mark me as Brainliest

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