Math, asked by sharmagabhishek621, 9 months ago

(x-y)(y-z)(z-x)/(x-y)^3+(y-z)^3+(z-x)^3

Answers

Answered by AnshMittal123
2

Sufficient answer

Brainliest

Attachments:
Answered by namrataag2006
0

(x-y) +(y-z) +(z-x) =0

hence,

(x-y) ^3+(y-z) ^3+(z-x) ^3 = 3(x-y) (y-z) (z-x)

hence,

(x-y) (y-z) (z-x) /(x-y) ^3+(y-z) ^3+(z-x) ^3=1/3

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