√x+√y+√z=0 than (x-y+z/xz)^2=
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3
therefore (x-y+z/xz)^2=3(x-y+z/xz) according to formulae
rudraroy894gmailcom:
wrong answer
wright answer 4
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0
hope answer is 4
tysm
tysm
please explain
hi
leeza
hello
your answer is correct.i requested to you for explain this math
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