Question

x+y+z=0 then prove that x*3+y*3+z*3=3xyz

Answer 1

here's your answer.

x+y+z=0
x+y=-z
cubing on both sides
(x+y)^3= (-z)^3
x^3+y^3+3xy(x+y)= -z^3
we know that x+y=-z
so, it becomes,
x^3+y^3+3xy(-z)=x^3+y^3-3xyz= -z^3
x^3+y^3+z^3=3zyz

hope this helps you
pls mark brainliest

Answer 2

Hii there!!

Plz refer to the attachment for the solution..

Hope it helps. ...