Question

X+y-z = 0 then (x^2- y^2)^2

Answer 1

Answer:

(x^2-y^2)^2

Step-by-step explanation:

given

X+y-z = 0

x+y=z

x^2+2xy+y^2=z^2

now

(x^2- y^2)^2

{(x+y)(x-y)}^2

(x+y)^2(x-y)^2

{x^2+2xy+y^2}{x^2-2xy+y^2}

x^2x^2-2x^3y+x^2y^2+2x^3y-4x^2y^2+2xy^3+x^2y^2-2xy^3+y^4

x^4-2x^2y^2+y^4

(x^2-y^2)^2