Math, asked by Mingyurpaldon172, 1 year ago

X+Y+Z =0 THEN (X+Y) (X+Z) (Y+Z) /XYZ+11=

Answers

Answered by ak4286
1
(a+b+c)^3 = a^3+b^3+c^3 + 3(a+b)(b+c)(a+c)

a^3+b^3+c^3 - 3 a b c = (a+b+c)(a^2+b^2+c^2 - a b - b c - a c)
use these two to solve
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