x+y+z=0 then x3+y3+z3=3xyz
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Answered by
13
x + y + z = 0
x + y = - z
(x + y )³ = (- z)³
x³ + y³ + 3xy (x + y ) = -z³
x ³ + y³ + 3xy ( - z ) = -z³
x³ + y³ - 3xyz = -z³
x³ + y³ + z³ = 3xyz (prooved )
x + y = - z
(x + y )³ = (- z)³
x³ + y³ + 3xy (x + y ) = -z³
x ³ + y³ + 3xy ( - z ) = -z³
x³ + y³ - 3xyz = -z³
x³ + y³ + z³ = 3xyz (prooved )
Answered by
6
x+y+z=0
x+y=-z
(x+y)3=-z3
x3+y3+z3-3(x+y)=-z3
x3+y3+z3=3xyz proved
x+y=-z
(x+y)3=-z3
x3+y3+z3-3(x+y)=-z3
x3+y3+z3=3xyz proved
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