Math, asked by argjila2004, 5 months ago

x+y+z=1 2x+4y+6z=2 -x+3y-5z=11

Answers

Answered by souravjha119777
3

Answer:

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Answered by GMADHUWALA
0
x+y+z=1
2x+4y+6z=2

X=1-z-y


2-2z-2y+4y+6z=2
2+2y+4z=2
2(1+y+2z)=2
1+y+2z=0
Y=-2z-1



2x+4y+6z=2
2-2z-2y+4y+6z=2
2+2y+4z=2
2+4z-2+4z=2
8z=2

Z=1/4

Y=-2z-1
Y=-2(1/4)-1
Y=(-1/2)-1

Y=(-3)/2


-x+3y-5z=11
-(x)+3((-3)/2)-5(1/4)=11
-9/2-5/4=11+x
-18/4-5/4-44/4=x

-67/4=x











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