Math, asked by internationalinox01, 6 months ago

x-y+z=1 x+y-z=-1 x+y+z=1

Answers

Answered by amishamay1318
0

Answer:

Step-by-step explanation:

x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)

x³+y³+z³=(x+y+z)(x²+y²+z²-xy-yz-zx)+3xyz

x³+y³+z³=1x(x+y+z)²-1+3x-1

=1-1-3

=-3

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