x+y+z=10 and x^2+y^2+z^2=40 find xy+yz+zx
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Answered by
1
(x+y+z)²=x²+y²+z²+2(xy+yz+zx)
100=40+2(xy+yz+zx)
60/2=xy+zx+yz
30=xy+yz+zx
100=40+2(xy+yz+zx)
60/2=xy+zx+yz
30=xy+yz+zx
Answered by
3
Hey ananya
your answer is here
as we know that (x+y+z)^2 = x^2+y^2+z^+2(xy+yz+xz)
by putting the value
100 = 40 + 2(xy+yz+zx)
Hence
xy+yz+zx = 30
Thanks
Be Brainy
your answer is here
as we know that (x+y+z)^2 = x^2+y^2+z^+2(xy+yz+xz)
by putting the value
100 = 40 + 2(xy+yz+zx)
Hence
xy+yz+zx = 30
Thanks
Be Brainy
ananya284:
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