Question

x+y+z=100 also (x*.50)+(y*3)+(z*10)=100 find x, y, z​

Answer 1

Answer:

Two equations, and three unknowns - you really cannot solve them for definite values can you? The best you can do is eliminate by multiplying through the first equation by 5050 and subtracting from the second. You get:

x+y+z=100x+y+z=100

−40y−49z=−4500−40y−49z=−4500

Now, you can express xx and yy in terms of zz, like this.

y=49z−450040,x=8500−89z40y=49z−450040,x=8500−89z40