Question

x + y + z = 12
xy+xz+yz=47
x^2+y^2+z^2=?​

Answer 1

Answer: x+y+z=12

xy+xz+yz=47

(x + y + z)² = (x² + y² + z²) + 2(xy + yz + zx)

(12)2= (x² + y² + z²)+2(47)

144=(x² + y² + z²)+94

144-94=x² + y² + z²

=>>x² + y² + z²=50

Hope it helps

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