Question

x+y+z= 15 and xyz =80 find the value of x,y and z​

Answer 1

Answer:

Let (y+z)=a

⟹x+a=42,ax=80

x+a=42

⟹(x+a)2=422

⟹x2+2ax+a2=1764

⟹x2+2ax+a2−4ax=1764−4(80)

⟹x2−2ax+a2=1444

⟹(x−a)2=1444

⟹x−a=±38

⟹x+a+x−a=42±38

⟹2x=42±38

⟹x=21±19

⟹x={2,40}

⟹a={40,2}

⟹⟹{x=2,y+z=40,x=40,(y+z)=2}