x+y+z= 15 and xyz =80 find the value of x,y and z
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Let (y+z)=a
⟹x+a=42,ax=80
x+a=42
⟹(x+a)2=422
⟹x2+2ax+a2=1764
⟹x2+2ax+a2−4ax=1764−4(80)
⟹x2−2ax+a2=1444
⟹(x−a)2=1444
⟹x−a=±38
⟹x+a+x−a=42±38
⟹2x=42±38
⟹x=21±19
⟹x={2,40}
⟹a={40,2}
⟹⟹{x=2,y+z=40,x=40,(y+z)=2}
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