Question

X+y+z=15, xy+yz+zx=71, xyz=10 then find the value of xcube+ycube+zcube=

Answer 1

Answer:

The solution given below by Satvik Bhatt below

Step-by-step explanation:

Formula to be used = (a+b+c) {a^2+b^2+c^2-(ab+bc+ca)}

Here, a=x

b=y

and c=z

As we don't use the same variable in the formula, given in the question.

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Answer 2

Solution

x³+y³+z³=(X+y+z)(x²+y²+z²-xy-yz-zx)

now...

x²+y²+z²

=(X+y+z)²-2(xy+yz+zx)

=15²-2(71)

=225-142

=83

now....

x³+y³+z³=(X+y+z)(x²+y²+z²-xy-yz-zx)

=(15)(83-71)=15×12=180

x³+y³+z³=180 (ans)

Hope this helps you......