Math, asked by yashica1056, 11 months ago

(x+y+z)^2 using suitable identity

Answers

Answered by devansh00gupta

0

(x+y+z) ^2 = x^2 +y^2+z^2+2xy +2yz+2zx

Answered by SVBS

0

X^2+y^2+z^2+2xy+2yz+2xz

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