Question

(x+y+z)²+(x+y/2+z/3)²-(x/2+y/3+z/4)²​

Answer 1

(x+y+z)²+(x+y/2+z/3)²-(x/2+y/3+z/4)

=x+y+z²+x+y/2+z/3²-x×2-y×3-z×4

=x+y+z²/2+z/3²×2×3×4

=x+y+z²/2+z/432