Question

(x +y+z)^2 - (x - y - z) ^2​

Answer 1

Answer:

Hello friend

Here's your answer

(x+y+z)²-(x-y+z)²

It is of the form a²-b²=(a+b)(a-b)

=(x+y+z+x-y+z)(x+y+z-(x-y+z))

=(2x+2z)(x+y+z-x+y-z)

=(2x+2z)2y

=4yx+4zy

Hope it helps!!

Answer 2

Answer:

(X+,y+z)² =x²+y²+z² +2xy+2yz+2zx(formula)

(x-y-z)²=x²+y ²+z²-2xy+2yz-2zx

so x²+y²+z²+2xy+2yz+2zx-(x²+y²+z²-2xy+2yz-2zx)

so, x²+y²+z²+2xy+2yz+2zx-x²-y²-z²+2xy-2yz+2zx

hence,. 4xy+4zx

=4x(y+z)