(x+y-z)^2+(x-y+z)^2
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Step-by-step explanation:
x²+y²-z²+x²-y²+z²
x^4-y^4-z^4. is the answer thanx.
Answered by
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Using The Method Of Expansions:
(x+y-z)^2 + (x-y+z)^2
= x^2 + y^2 + z^2 +2( xy-yz-xz) + x^2 + y^2 + z^2 +2(xz-xy-yz)
= x^2 + y^2 + z^2 + 2xy -2yz -2xz + x^2 + y^2 + z^2 +2xz - 2xy - 2yz
2xy, -2xz - 2yz + 2xz - 2xy -2yz will all cancel with each other....
= x^2 + y^2 + z^2 + x^2 + y^2 + z^2
= 2 x^2 + 2y^2 + 2z^2
= 2 (x^2 + y^2 + z^2) which is your final answer.
Hope it helps you.
Happy learning.
(x+y-z)^2 + (x-y+z)^2
= x^2 + y^2 + z^2 +2( xy-yz-xz) + x^2 + y^2 + z^2 +2(xz-xy-yz)
= x^2 + y^2 + z^2 + 2xy -2yz -2xz + x^2 + y^2 + z^2 +2xz - 2xy - 2yz
2xy, -2xz - 2yz + 2xz - 2xy -2yz will all cancel with each other....
= x^2 + y^2 + z^2 + x^2 + y^2 + z^2
= 2 x^2 + 2y^2 + 2z^2
= 2 (x^2 + y^2 + z^2) which is your final answer.
Hope it helps you.
Happy learning.
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