Question

(x+y+z)² = x² + y² + z² + 2xy+2yz+2xz. (x+y–z)² = x² + y² + z² + 2xy–2yz–2xz. (x–y+z)² = x² + y² + z² –2xy–2yz+2xz

Answer 1

Answer:

(x + y + z)?

Compare this with (a + b)?, whereas {a = x = and b = (y + z) }

As we know (a + b)2 = a? + b2 + 2ab =

On Applying formula, we get

(x + y + z)2

=> x? + (y + z)2 + 2x(y + z)

=> x2 + y2 + z2 + 2yz + 2xy + 2xz