(x+y+z) 2=x2+y2+z2+2xy+2yz+2zx
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it is a formula of (x+y+z)^2 it will come from when we multiply (x+y+z)(x+y+z)
Answered by
30
(x + y + z)²
Compare this with (a + b)², whereas { a = x and b = (y + z) }
As we know (a + b)² = a² + b² + 2ab
On Applying formula, we get
(x + y + z)²
=> x² + (y + z)² + 2x(y + z)
=> x² + y² + z² + 2yz + 2xy + 2xz
Hence, proved.
Compare this with (a + b)², whereas { a = x and b = (y + z) }
As we know (a + b)² = a² + b² + 2ab
On Applying formula, we get
(x + y + z)²
=> x² + (y + z)² + 2x(y + z)
=> x² + y² + z² + 2yz + 2xy + 2xz
Hence, proved.
Bharatpalrawat:
very thankful
:-)
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