Question

(x+y-z)2+(y+z-x)2+(z+x-y)2=0 find x+y+z

Answer 1

Answer:

0

Step-by-step explanation:

(x+y-z)2+(y+z-x)2+(z+x-y)2=0

2x + 2y - 2z + 2y + 2z - 2x + 2z + 2x - 2y = 0

2x + 2y + 2z = 0

2 ( x + y + z) = 0

x + y + z = 0