Question

(x+y-z) +(3x-4x+7z)-(20x+7y-6x)​

Answer 1

Answer:

$\mathrm{\left(x+y-z\right)+\left(3x-4x+7z\right)-\left(20x+7y-6x\right)=-14x-6y+6z}$

Step-by-step explanation:

$\mathrm{\left(x+y-z\right)+\left(3x-4x+7z\right)-\left(20x+7y-6x\right)}$

$\mathrm{Remove\:parentheses:\quad \left(a\right)=a}$

$=\mathrm{x+y-z+3x-4x+7z-\left(20x+7y-6x\right)}$

$\mathrm{=x+y-z+3x-4x+7z-\left(14x+7y\right)}$

$\mathrm{=x+y-z+3x-4x+7z-14x-7y}$

$\mathrm{=-14x-6y+6z}$