x-y+z=4,2x+y-3z=0,x+y+z=2??
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Answer:
by elimination method
Step-by-step explanation:
Given equations
x – y + z = 4
2x + y – 3z = 0
x + y + z = 2
We can write this system of equations as AX = B where
= 1(1 + 3) - (- 1) (2 + 3) + 1 (2 - 1) = 4 + 5 + 1 = 10 ∴ A–1 exists.
A11 = 4,
A12 = –5,
A13 = 1
A21 = 2,
A22 = 0,
A23 = –2
A31 = 2,
A32 = 5,
A33 = 3
The required solution is ∴ x = 2, y = - 1, z = 1
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