x:y:z=4:5:6 then find x,y,z if they are on a straight line XOY
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Answered by
3
ratio=4:5:6
sum of ratio=4+5+6=15
x=4/15*180°=48°
y=5/15*180°=60°
z=6/15*180°=72°
sum of ratio=4+5+6=15
x=4/15*180°=48°
y=5/15*180°=60°
z=6/15*180°=72°
riyu32:
thanks for the answer
Answered by
6
let the given ratio be a
x=4a
y=5a
z=6a
XYZ is a straight line
x+y+z=180
4a+5a+6a=18
a=180/15
a=12
putting value of a
x=4×12
=48
y=5×12
=60
z=6×12
=72
hope it will helpful..
mark as brainlist....
x=4a
y=5a
z=6a
XYZ is a straight line
x+y+z=180
4a+5a+6a=18
a=180/15
a=12
putting value of a
x=4×12
=48
y=5×12
=60
z=6×12
=72
hope it will helpful..
mark as brainlist....
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