x+y+z=5;2x_y+z=9;x_2y+3z=16
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Answer:
Given,
x + y + z = 5 .....(1)
2x - y + z = 9 .....(2)
x - 2y + 3z = 16 .....(3)
Subtracting (2) from (1);
- x + 2y = -4 .....(4)
Multiplying (1) by 3 and subtracting (3) from the product;
2x +5y = -1 ......(5)
Solving (4) and (5), we get;
x = 2 and y = -1
Hence, z = 4
Therefore,
x = 2 \: \: y = -1 \: \: z = 4x=2y=−1z=4
HOPE THIS COULD HELP!
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