Question

x+y+z=6,2x+3y-z=5,6x-2y-3z=-7
solve in echlon form method

​

Answer 1

Explanation:

Δ=

∣

∣

∣

∣

∣

∣

∣

∣

2

1

1

−1

1

−1

3

1

1

∣

∣

∣

∣

∣

∣

∣

∣

=2(1+1)−(−1)(1−1)+3(−2)=4−6=−2

Now, Δ

x

=

∣

∣

∣

∣

∣

∣

∣

∣

9

6

2

−1

1

−1

3

1

1

∣

∣

∣

∣

∣

∣

∣

∣

=14

Δ

y

=

∣

∣

∣

∣

∣

∣

∣

∣

2

1

1

9

6

2

3

1

1

∣

∣

∣

∣

∣

∣

∣

∣

=−2

Δ

z

=

∣

∣

∣

∣

∣

∣

∣

∣

2

1

1

−1

1

−1

9

6

2

∣

∣

∣

∣

∣

∣

∣

∣

=−6

So,According to Cramer's Rule x=

Δ

Δ

x

=

−2

14

=−7

y=

Δ

Δ

y

=

−2

−2

=1

z=

Δ

Δ

z

=

−2

−6

=3