x +y+z=6
3x-y+2z=8
X-y +z=2
X?
Y.?
Z?
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Answered by
1
Answer:
I don't know the answer sooooooooooo sorry
Answered by
1
Given that,
x+y+z=6 ..........(1)
3x-y+2z=8 ........(2)
x-y+z=2 .......... (3)
From equation (1), we get
x+y+z=6
=> z = 6-x-y ........(4)
Putting these value in 3, we get
x-y+z=2
=> x-y+(6-x-y)=2
=>
x+y+z=6 ..........(1)
3x-y+2z=8 ........(2)
x-y+z=2 .......... (3)
From equation (1), we get
x+y+z=6
=> z = 6-x-y ........(4)
Putting these value in 3, we get
x-y+z=2
=> x-y+(6-x-y)=2
=>
anand261660:
Uncomplicated
From here you can find the value of y and put it into any of the equation ...... in the same manner you can also find the value of x and y
Best of luck
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