Question

x+y+z=6, 3x-y+3z=10 , 5x+5y-4z=3​

Answer 1

Step-by-step explanation:

x+y+z= 6

x= 6-y-z (1)

putting the value of x in eq(2)

3x-y+3z=10

3(6-y-z)-y+3z=10

18-3y-3z-y+3z=10

18-4y= 10

4y= 18-10

y= 8/4= 2 (2)

Now putting the value of x and y in eq(3)

5x+5y-4z=3

5(6-y-z)+5(2)-4z= 3

30-5(2)-5z+10-4z=3

30-10+10-9z=3

30-9z= 3

30-3= 9z

z= 27/9= 3

therefore x= (6-2-3)= 1

x=1

y=2

z=3