Question

x+ y+z=6 and xy+yz+zx=9 then prove that 1÷(1-x)+1÷(1-y)+1÷(1-z)=0​

Answer 1

Answer:

0

Step-by-step explanation:

we have given, x+y+z=6 and xy+yz+zx=9...a

hence we can write x=6-y-z...1

from prove equation,

1÷(1-6+y+z)+1÷(1-y)+1÷(1-z)=0

1÷(-5+y+z)+1÷(1-y)+1÷(1-z)=0

1÷-5+y+z+1÷1-y+1÷1-z=0

1÷-4+y+z÷2-y÷1-z=0

1/-4+y+z × 1-z/2-y=0

1-z/(-4+y+z)(2-y)=0

1-z/y^2-6y-2z+yz+8=0

from ...a

yz=9-xy-zx

1-z/y^2-6y-2z+9-xy-zx+8=0

.....