Question

x+y+z=6,x+2z=7,3x+y+z=12​

Answer 1

Answer:

(x,y,z)=(3,1,2)

Step-by-step explanation:

solving 1st and 3rd equation we would get as

2x=6

x=3

substituting the value in 2nd eqn we get as

3+2z=7

2z=4

z=2

substituting both the values in 1st eqn we get as

3+y+2=6

5+y=6

y=1