x+y+z=6, x-y+z=2,x+2y-z=2
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Answer:x+y+z=6----------(1)
x-y+z=2-------------(2)
x+2y-z=2-------------(3)
add equation 1 and 3
x+y+z=6
x+2y-z=2
_________
2x+3y=8--------(4) with the help of elimination method
Again add equation 2 and 3
x-y+z=2
x+2y-z=2
_________
2x+y=4-------(5)
Substracting equation 4 and 5
x+3y=8
x+y=4
_______
2y=4
y= 2
Put these value from eq.(5)
x+y=4
x+2=4
x=2
Put x and y value from eq.(1)
x+y+z=6
2+2+z=6
z=2
Step-by-step explanation:
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