Question

x+y+z=6 , xyz=6. xy+yz+zx=11. find x^3+y^3+z^3

Answer 1

Cubing on both side
(X+Y+Z)^3=(6)^3 X^3+Y^3+Z^3+3XYZ(XY+YZ+ZX)=216
X^3+Y^3+Z^3+3*6*11=216
X^3+Y^3+Z^3=216-198
X^3+Y^3+Z^3=18

I HOPE THIS WILL HELP U
BY DEVANSH

Answer 2

Answer:

X³+Y³+Z³ = 18

Step-by-step explanation:

(X+Y+Z )³= X³+Y³+Z³ +3XYZ( XY +YZ+ZX)

Putting the given values in the above equation

6³ = X³+Y³+Z³+3×6×11

216= X³ +Y³+Z³ +198

X³+Y³+Z³ = 216 -198

               =18.

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