x+y+z=6 , xyz=6. xy+yz+zx=11. find x^3+y^3+z^3
Answers
Answered by
9
Cubing on both side
(X+Y+Z)^3=(6)^3 X^3+Y^3+Z^3+3XYZ(XY+YZ+ZX)=216
X^3+Y^3+Z^3+3*6*11=216
X^3+Y^3+Z^3=216-198
X^3+Y^3+Z^3=18
I HOPE THIS WILL HELP U
BY DEVANSH
(X+Y+Z)^3=(6)^3 X^3+Y^3+Z^3+3XYZ(XY+YZ+ZX)=216
X^3+Y^3+Z^3+3*6*11=216
X^3+Y^3+Z^3=216-198
X^3+Y^3+Z^3=18
I HOPE THIS WILL HELP U
BY DEVANSH
BEJOICE:
Hi, How you got this expansion for (x+y+z)^3
By cubing
It is not correct
It is a formula
Correct
In the formula u wrote 3xyz(xy+yz+xz). After expanding x^2y^2z term comes
Means sum of powers 2+2+1 = 5
Then how it is correct
Then how it is correct
Answered by
0
Answer:
X³+Y³+Z³ = 18
Step-by-step explanation:
(X+Y+Z )³= X³+Y³+Z³ +3XYZ( XY +YZ+ZX)
Putting the given values in the above equation
6³ = X³+Y³+Z³+3×6×11
216= X³ +Y³+Z³ +198
X³+Y³+Z³ = 216 -198
=18.
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