Question

x+y+z=7,5x+4y-3z=1,6x-3y+2z=8

Answer 1

Answer:

what to find.....????

Answer 2

Step-by-step explanation:

x+y+z=7 .........(1)

1] x + y + z = 7

[2] 5x + 4y - 3z = 1

[3] 6x - 3y + 2z = 8

Solve by Substitution :

// Solve equation [1] for the variable z

[1] z = -x - y + 7

// Plug this in for variable z in equation [2]

[2] 5x + 4y - 3•(-x -y +7) = 1

[2] 8x + 7y = 22

// Plug this in for variable z in equation [3]

[3] 6x - 3y + 2•(-x -y +7) = 8

[3] 4x - 5y = -6

// Solve equation [3] for the variable x

[3] 4x = 5y - 6

[3] x = 5y/4 - 3/2

// Plug this in for variable x in equation [2]

[2] 8•(5y/4-3/2) + 7y = 22

[2] 17y = 34

// Solve equation [2] for the variable y

[2] 17y = 34

[2] y = 2

// By now we know this much :

x = 5y/4-3/2

y = 2

z = -x-y+7

// Use the y value to solve for x

x = (5/4)(2)-3/2 = 1

// Use the x and y values to solve for z

z = -(1)-(2)+7 = 4

Solution :

{x,y,z} = {1,2,4}