Question

x+Y+z =7, 5x+4y-3z=1, 6x-3y+2z=8 solve by elimination method find x Y and z​

Answer 1

Answer:

x=1

y=2

z=4

(1)*5-(2)

y+8z=34----(4)

,(1)*6-(3)

9y+4z=34---(5)

(5)*2-(4)

y=2

put y=2 in(4)

z=4

x=1