Math, asked by scrapper, 9 months ago

x+y+z=8 and xy+yz+zx=20 find x³+y³+z³-3xyz​

Answers

Answered by borapriya112
4

Answer: 32

Step-by-step explanation:

(x+y+z)³=x³+y³+z³+3{(x+y+z)(xy+yz+zx)-xyz}

= 8³ =x³+y³+z³+3(8*20-xyz)

= 512= x³+y³+z³+3(160-xyz)

= 512 =x³ +y³ +z³ +480-3xyz

= x³+y³+z³ -3xyz = 512 -480

Hence, x³+y³+z³-3xyz =32

Answered by KJB811217
3

Step-by-step explanation:

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