Question

X/y+z = a ,x/z+x = b, z/x+y =c, then 1/1+a + 1/1+b + 1/1+c

Answer 1

Answer:

X/y+z = a ,y/z+x = b, z/x+y =c

1/1+a = 1/(1 + x/y+z )

       = 1/(x+y+z)/(y+z)

       =(y+z) / (x+y+z)

1/1+b = 1/(1 + y/z+x )

       = 1/(x+y+z)/(z+x)

       =(z+x) / (x+y+z)

1/1+c = 1/(1 + z/x+y )

       = 1/(x+y+z)/(x+y)

       =(x+y) / (x+y+z)

1/1+a + 1/1+b + 1/1+c = (y+z) / (x+y+z) + (z+x) / (x+y+z) + (x+y) / (x+y+z)

= 2(x+y+z) /  (x+y+z)

= 2

Hope this helps. Happy learning!!!