Question

X,y,z are in proportion.Find. Y ifx=8,z=32

Answer 1

Answer:

Given that x,y and z are in proportion

Therefore,

x:y = y:z

$\frac{8}{y} = \frac{y}{32} \\ = > {y }^{2} = 256 \\ = > y = \sqrt{256} \\ = > y = 16$

Therefore, y = 16

Hope it helps mate, good luck.

Please mark me as brain list only if you think I deserve.