x, y, z are positive real numbers which satisfy the following three equations.
x + 2y + z = 5(x + y)(y + z)
x + y + 2z = 7(y + z)(z + x)
2x + y + z = 6(z + x)(x + y).
Find the value of (24)³×(xyz).
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Answer:
x+2y+z=5(xy+xz+y²+yz)
x+2y+z=5xy+5xz+5y²+5yz
x-5xy-5xz=5y²+5yz-2y
x(1-5y-5z)=y(5y+5z-2)
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