Question

x, y, z are three real numbers x<y and z<0 if (a)x×y<y×z (b)x×z>y×z (c)x×z≤y×z (d)x×z=y×z​

Answer 1

SOLUTION

TO CHOOSE THE CORRECT OPTION

x, y, z are three real numbers x < y and z < 0 then

(a) x ×y < y×z

(b)x×z > y×z

(c) x×z ≤ y×z

(d)x×z = y×z

EVALUATION

Here it is given that x, y, z are three real numbers with

x < y and z < 0

$\sf{x < y}$

On multiplication with z ( < 0 ) we get

$\sf{x \: \times \: z \: > y \: \times \: z}$

Hence the correct option is (b) x×z > y×z

VERIFICATION

Let us take x = 1 , y = 2 & z = - 3

Then x < y so that xz = - 3 & yz = - 6

∴ x×z > y×z

Hence verified

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Answer 2

Answer:

x, y and zop are three real number numbers. If x<y and z < 0 then