X+y=z....prove that.....x cube -y cube-z cube....3xyz=0
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Answer:x+y=z
X+y-z=0
Cube both sides
X cube + y cube -z cube =0 cube
Identity x cube + y cube +z cube -3(x)(y) (z)
X cube+ y cube +z cube 3(x)(y) (z) =0
Hence proved
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