Question

x=y+z then find the value of x^3 _y^3 _z^3​

Answer 1

Answer:

substitute (x=y+z) in the secone equation.

Step-by-step explanation:

(y+z)^3  - y^3 -z^3

{since   (a+b)^3   =    a^3 +  b^3 +  3ab(a+b)   }

y^3 + z^3 +3yz(y+z) - y^3 -z^3

=3yz(y+z)

Answer 2

Solution:

It is given that,

x = y+z ----(1)

On cubeing both sides of the equation, we get

=> x³ = (y+z)³

=> x³ = y³+z³+3yz(y+z)

=> x³-y³-z³ = 3yzx /*from (1)*/

Therefore,

x³-y³-z³ = 3xyz

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