Math, asked by mohmmadyusuf111974, 6 months ago

(x+y+z)(x-y+z)+(x+y-z)(-x+y+z)-4zx

Answers

Answered by Anonymous
10

Answer:

\huge{\underline{\underline{\tt{\purple{QUESTION}}}}}

Q. (x+y+z)(x-y+z)+(x+y-z)(-x+y+z)-4zx

\huge{\underline{\underline{\tt{\blue{ANSWER}}}}}

=> x(x-y+z)+y(x-y+z)+z(x-y+z) + x(-x+y+z)+y(-x+y+z)-z(-x+y+z) - 4zx

=> x²- xy+xz + xy-y²+yz + xz-yz+z² - x²+xy+xz -xy+y²+yz + xz-yz-z²- 4zx

=> x²-x²+2xy-2xy + 2zx+2zx-4zx -y²+y² +2yz-2yz + z²-z²

=> 0

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HOPE IT HELPS YOU!!!!

Answered by Anonymous
22

\huge{\underline{\underline{\tt{\blue{QUESTION}}}}}

Q. (x+y+z)(x-y+z)+(x+y-z)(-x+y+z)-4zx

✧✦✧✦✧✦✧✦✧✦✧✦✧✦✧✦✧✦✧✦✧✦✧

\huge{\underline{\underline{\tt{\red{SOLUTION}}}}}

=> x(y+z)+y(x-y+z)+z(x-y+z) + x(-z)+y(-x+y+z)-z(-x+y+z) - 4zx

=> x²- xy+xz + xy-y²+yz + xz-yz+z² - x²+xy+xz -xy+y²+yz + xz-yz-z² - 4zx

=> x²-x²+2xy-2xy + 2xz+2xz-4zx -y²+y² +2yz-2yz + z²-z²

=> 0

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✯ HOPE IT HELPS YOU!!!! ✯

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