Question

x’y’z’+x’y’z+x’yz+x’yz’+xy’z+xy’z=x’+y’z. Prove it using boolean algebra

Answer 1

Answer:

just you need to know is

a + a' = 1

and

a . 1 = 1

and you can start simplification

i assumed that your either last or second last term is incorrect and it should be x'y'z

now equation is

x'y'z' + x'y'z + x'yz + x'yz' + xy'z + x'y'z

x'y'( z' + z ) + x'y( z + z' ) + y'z( x + x')

x'y' . 1 + x'y . 1 + y'z . 1

x'y' + x'y + y'z

x'( y' + y ) + y'z

x' . 1 + y'z

x' + y'z

hence proved

Explanation:

Hope it helps :-)