(x+y+z)=x²+y²+z²+2xy+2yz+2xz
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Answered by
2
yes this is an identity of square of three variables
this can be checked simply by inserting the values
this can be checked simply by inserting the values
Answered by
2
(x+y+z)² = (x+y +z)(x+y +z)
=> (x+y+z)² =x²+y²+z²+2xy+2yz+2xz
=> (x+y+z)² =x²+y²+z²+2xy+2yz+2xz
Nabuboy:
(x+y+z)2equals...considering x+y as. ...a...and dan applyin (a+b)2
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