Math, asked by sagarika50, 10 months ago

x(y-z)+y(z-x)+z(x-y)

Answers

Answered by Anonymous

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$<font color="blue">$

=xy-xz+yz-xy+zx-yz

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Answered by aasimashade

Answer:

xy-xz+zy-xz+xz-zy

every term has both positive and negative so they cut down.so the answer is zero

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x(y-z)+y(z-x)+z(x-y)